And so this would simply be equaling to the fundamental frequency of the first shrink multiplied by the square root of the force. Ah, Jeff over for length squared mu and then multiplied by f prime divided by f, this algebraic lee makes sense. If a second, identical call string with attention f crime, this is going to be less than F if that struck that the fundamental frequency of that vibration would be f the fundamental frequency prime would be the square root of F crime divided by four I'll square and mu, and this is gonna be equaling to the square root.
And so this would be equal in the square root of the force over four l squared, mute, and so in. This would be equaling 21 over two times the length multiplied by the square root of the tension force, divided by the linear density, the linear mass density. And so the fundamental frequency can then be ricin as the over the fundamental wavelength. So we can say the fundamental wavelength would be equaling two times the length. This means that the length of the string is equal to half two a half wavelength on the fundamental resident's frequency.
